solve this problem question no 7
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a = b/(b-1) .........
Sanathkr:
sorry but I need the full solution
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We Know that log a + log b = log ab.
Given that RHS = log a + log b
= log (ab).
Therefore LHS = RHS
log(a + b) = log(ab)
a + b = ab
b = ab - a
= a(b - 1)
a = b/(b - 1).
Hope this helps!
Given that RHS = log a + log b
= log (ab).
Therefore LHS = RHS
log(a + b) = log(ab)
a + b = ab
b = ab - a
= a(b - 1)
a = b/(b - 1).
Hope this helps!
Thanks for the brainliest dude
ur welcome
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