Question

Solve this problem

$2 {}^{4x} \times 4 {}^{3x - 1} = \frac{4 {}^{2x} }{2 {}^{3x} }$
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Answer 1

Answer:

2^4x x4^3x-1 = 4^2x/2^3x

2^4x x 2^2 (3x-1) = 2^4x / 2^3x

2^4× x 2^ 6x-2= 2^4x / 2^ 3x

2^( 4x-6x+2)= 2^ (4x-3x)

2^ ( -2x +2) = 2^ x

-2x +2 =x

-3x= -2

x= 2/3