solve this problem . this is probablity sum
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Answer :-
a) 1 / 2
b) 1 / 2
Solution :-
Sample space n( S ) = 1, 2, 3, 4, 5, 6
No. of possible outcomes = n( S ) = 6
a) a prime number
Let the event 'P' be " a prime no. "
Favourable outcomes = 2, 3, 5
No. of favourable outcomes n( P ) = 3
Probability P( P ) = n( P ) / n( S ) = 3 / 6 = 1 / 2
b ) an odd number
Let the event 'O' be " an odd no. "
Favourable outcomes = 1, 3, 5
No. of favourable outcomes n( O ) = 3
Probability P( O ) = n( O ) / n( S ) = 3 / 6 = 1 / 2
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