solve this problem urgent with kirchoff's law
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Equivalent resistance in the given circuit is 5+10 = 15 ohm
equivalent potential difference in a given circuit is
12+6 = 18 V
V = 18 V
R = 15 ohm
V = IR
18 = I × 15
I = 18/15
I = 1.2 A
potential drop across resistor 10 ohm is equals to
V = IR
V = 1.2 × 10
V = 12 V
potential drop across resistor of 5 ohm is equals to
V = IR
V = 1.2 × 5
V = 6 V
here is ur answer
I hope it helps you
if so plz brainliest
equivalent potential difference in a given circuit is
12+6 = 18 V
V = 18 V
R = 15 ohm
V = IR
18 = I × 15
I = 18/15
I = 1.2 A
potential drop across resistor 10 ohm is equals to
V = IR
V = 1.2 × 10
V = 12 V
potential drop across resistor of 5 ohm is equals to
V = IR
V = 1.2 × 5
V = 6 V
here is ur answer
I hope it helps you
if so plz brainliest
Answered by
1
Equivalent resistance in the given circuit is 5+10 = 15 ohm
equivalent potential difference in a given circuit is
12+6 = 18 V
V = 18 V
R = 15
V = IR
18 = I × 15
I = 18/15
I = 1.2 A
potential drop across resistor 10 ohm is equals to
V = IR
V = 1.2 × 10
V = 12 V
V
potential drop across resistor of 5 ohm is equals to
V = IR
V = 1.2 × 5
V = 6
here is ur answer
I hope it helps you
if so plz brainliest
equivalent potential difference in a given circuit is
12+6 = 18 V
V = 18 V
R = 15
V = IR
18 = I × 15
I = 18/15
I = 1.2 A
potential drop across resistor 10 ohm is equals to
V = IR
V = 1.2 × 10
V = 12 V
V
potential drop across resistor of 5 ohm is equals to
V = IR
V = 1.2 × 5
V = 6
here is ur answer
I hope it helps you
if so plz brainliest
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