solve this problem with solution please
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y=4x and x+y=10
5x=10, x=2
and y=8
5x=10, x=2
and y=8
AnushmitaRay:
answer is 82
Answered by
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let the digit in tens place be y and that at the unit place be x.
THE NUMBER BECOMES = 10(X)+Y
ATQ,CASE1
four times digit of units place=
y=4x
ATQ, CASE 2
X+Y=10--------(1)
NOW, SUBSTITUTING THE VALUE OF Y IN EQUATION 1
X+4X=10
5X=10
X=10/5=2
NOW PITTING THE VALUE OF X IN THE VALUE OF Y=4X
Y=4(2)=8
THEREFORE THE NUMBER IS 10(2)+8=20+8=28
HOPE IT HELPS YOU.
PLEASE MARK IT AS BRAINLIEST.
THE NUMBER BECOMES = 10(X)+Y
ATQ,CASE1
four times digit of units place=
y=4x
ATQ, CASE 2
X+Y=10--------(1)
NOW, SUBSTITUTING THE VALUE OF Y IN EQUATION 1
X+4X=10
5X=10
X=10/5=2
NOW PITTING THE VALUE OF X IN THE VALUE OF Y=4X
Y=4(2)=8
THEREFORE THE NUMBER IS 10(2)+8=20+8=28
HOPE IT HELPS YOU.
PLEASE MARK IT AS BRAINLIEST.
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