Question

solve this problem y/2-1/2=y/3+1/4​

Answer 1

Step-by-step explanation:

$\huge\sf\underline\blue{answer}$

$\frac{y}{2} - \frac{1}{2} = \frac{y}{3} + \frac{1}{4}$

$\frac{y}{2} - \frac{y}{3} = \frac{1}{4} + \frac{1}{2}$

$\frac{3y - 2y}{6} = \frac{1 + 2}{4}$

$\frac{y}{6} = \frac{3}{4}$

$4y = 18$

$y = \frac{18}{4}$

$y = \frac{9}{2}$

.: y = 9/2

Answer 2

Step by step explanation:

Given :-

$\sf\dfrac{y}{2} - \sf\dfrac{1}{2} = \sf\dfrac{y}{3} + \sf\dfrac{1}{4}$

Solution:-

$\sf\dfrac{y}{2} - \sf\dfrac{1}{2} = \sf\dfrac{y}{3} + \sf\dfrac{1}{4}$

Take LCM On RHS

L.C.M of 3, 4 is 12

$\sf\dfrac{y-1}{2} = \sf\dfrac{4 \times y + 3 \times 1}{12}$

Simplify The RHS

$\sf\dfrac{y-1}{2} = \sf\dfrac{4y + 3}{12}$

Cross multiply the terms

(y-1) 12 = (4y+3) × 2

12y-12 = 8y + 6

Transpose like terms to side

12y - 8y = 6 +12

4y = 18

Make a subject y

$\sf\dfrac{4y}{4} = \sf\dfrac{18}{4}$

y = $\sf\dfrac{18}{4}$

Simplify the value of y

18 can be written as 2×9

4 can be written as 2 ×2

y = $\sf\dfrac{2 \times 9}{2 \times 2}$

y = $\sf\dfrac{9}{2}$

So, required value of y is 9/2