Physics, asked by kaushik05, 10 months ago

solve this properly ​

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Answered by Anonymous
34

 \huge{ \underline{ \underline{ \green{ \sf{ Detailed \: Answer :}}}}}

  • To find: the time period of the combination
  • time period of oscillation in a vibration magnetometer,T = 2 seconds

we know that , time period of oscillation of magnet ;

T = 2π √I/(MB)

Where , I = moment of inertia of magnet

M = magnetic moment

Moment of Inertia of magnet

I =   \frac{1}{12} ml {}^{2}

When it cut into three equal parts ,

the length of each piece of magnet is l/3

↪Moment of Inertia of the combination

I'=  \frac{1}{12}  \times  \frac{m}{3}  \times  (\frac{l {}^{} }{3} ) {}^{2}  \times 3

 =  \frac{ml {}^{2} }{9×12}

I'=  \frac{I}{9}

{\red{\boxed{\large{\bold{Magnetic\: moment = pole\: strgenth × length}}}}}

M'= m \times  \frac{l}{3}  \times 3

M'= M

T' = 2\pi \sqrt{ \frac{I'}{M\times B} }

T'= 2\pi  \sqrt{  \frac{ \frac{I}{9} }{MB} }

Now divide i.e T'/T

T'=  \frac{t}{3}

T'=  \frac{2}{3}

∴ correct option B) 2/3 sec


kaushik05: thnks
Answered by Tanvi2407
4

Answer:

Option B is yr answer.

Explanation:

Hope it helps:))

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