solve this proptional question
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if a²+c² ab+cd and b²+d² are in continuous proportion we write that as a²+c²:ab+cd::ab+cd:a²+c²
so (ab+cd)²= (a²+c²)(b²+d²)
a²b²+2abcd+c²d²= a²b²+a²d²+b²c²+c²d²
2abcd=a²d²+b²c²
a²d²+b²c²-2abcd=o
(ad-bc)²=0
ad-bc=o
ad=bc.
a/b=c/d
prooved
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