Math, asked by parthuteja, 10 months ago

Solve this puzzle..
Person A work complete in 20 days.. Person B work complete work in 30 days. If persons A , B, &C together work completed in 7 days. Total work value Rs 6000/-. Then what share will get to Person C?​

Answers

Answered by RvChaudharY50
28

Gɪᴠᴇɴ :-

  • A complete work in = 20 days.
  • B complete work in = 30 Days.
  • (A + B + C) complete work in = 7 Days.
  • Total work value = Rs.6000 .

Tᴏ Fɪɴᴅ :-

  • share of C ?

ᴄᴏɴᴄᴇᴘᴛ ᴜsᴇᴅ :-

  • The money Paid is In the ratio of Their Efficiency when they do same work together ...

Sᴏʟᴜᴛɪᴏɴ :-

LCM of (20,30,7) = 420 units = Let Total work done.

Than,

Efficiency of A = (Total work) / (Total No. of Days). = (420/20) = 21 unit/Day.

Efficiency of B = (Total work) / (Total No. of Days). = (420/30) = 14 unit/Day.

→ Efficiency of (A+B+C) = (Total work) / (Total No. of Days). = (420/7) = 60 unit/Day.

So,

Efficiency of C = (A + B + C) - A - B = 60 - 14 - 21 = 25 unit/day.

Therefore,

share of A : B : C = 21 : 14 : 25

And,

share of C = (25/60) * 6000 = Rs.2500 (Ans.)

Hence, Rs.2500 share will get to Person C..

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