Solve this Q. 30 in this pic
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(0.101)2=2^-1*1+2^-2*0+2^-3*1=1/2+0+1/8=5/8
(0.011)2=0*2^-1+1*2^-2+1*2^-3=0+1/4+1/8+=3/8
(11)2=1*2^1+1*2^0=3
(01)2=0*2^1+1*2^0=1
Therefore, ={(5/8)^3+(3/8)^3}/(5/8)^2-(5/8)(3/8)+(3/8)^2
=5/8+/8=8/8=1=(1)2
(0.011)2=0*2^-1+1*2^-2+1*2^-3=0+1/4+1/8+=3/8
(11)2=1*2^1+1*2^0=3
(01)2=0*2^1+1*2^0=1
Therefore, ={(5/8)^3+(3/8)^3}/(5/8)^2-(5/8)(3/8)+(3/8)^2
=5/8+/8=8/8=1=(1)2
Answered by
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1 is the answer.......
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