Question

Solve this:

Q. The graph between the displacement x and time t for a particle moving in a straight line is shown in the figure. During the interval OA, AB, BC and CD, the acceleration of the particle is

OA AB BC CD
(A) + 0 + +
(B) – 0 + 0
(C) + 0 – +
(D) – 0 – 0

Answer 1

Answer:

option c

Explanation:

+ 0 - +

is the answer of this question

Answer 2

Answer:

(b)- 0 + 0

Explanation:

As we can see that the parabola goes in downward direction in interval OA thus, indicating -ve. It stays uniform at AB then at BC, again acceleration takes place or you can also identify by seeing the shape of parabola which is in upward direction, indicating +ve. At CD we see that there is no acceleration thus indicating 0 acceleration.

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