Question

solve this quadratic equation :
(2+ i)x²- (5-i) x +2 (1-1) = 0​

Answer 1

Answer:

x= 0 aur i = 5 rakh lo aa jayega ans

Answer 2

Step-by-step explanation:

(2+i)x^2-(5-i)x+0=0

(2+i)x^2-(5-i)x=0

x((2+i)x-5+i)=0

x=0,

(2+i)x=i-5

x=i-5/2+i