SOLVE THIS QUADRATIC EQUATION:
2a²-8a+57=0
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by comparing equation 2a²-8a+57=0 by ax^2+by+c=0
then we have,
a=2, b=-8, c=57
To find x by quadric equation.. formula:
x=[-b+-√(b^2-4ac)]/2a
x=[-(-8)+-√(8^2-4×57)]/2×2
x=[8+-√(64-4×2×57)]/4]
x=2+-√(64-456)
x=2+-√-392
x=2+-√-392i
x=2+-√(14×14×2)i
x=2+-14√2i
x=2+14√2i ,x=2-14√2i.
then we have,
a=2, b=-8, c=57
To find x by quadric equation.. formula:
x=[-b+-√(b^2-4ac)]/2a
x=[-(-8)+-√(8^2-4×57)]/2×2
x=[8+-√(64-4×2×57)]/4]
x=2+-√(64-456)
x=2+-√-392
x=2+-√-392i
x=2+-√(14×14×2)i
x=2+-14√2i
x=2+14√2i ,x=2-14√2i.
nitin104:
ur method is correct and ur ans is also correct
is it correct...
now this is correct
now it is correct
yes
bye i want to study for tomorrow s paper
so go fast
nd all the best
bye
thnx
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