Math, asked by KD12345, 11 months ago

Solve this quadratic equation (2x-3)(3x+1)= 0

Answers

Answered by AkshitBedi07
1

Answer:zero of 1st polynomial will be 3/2 and second will be - 1/3

Step-by-step explanation:

After the steps solved we will answer them separately

2x-3=0

2x=-3

X=-3/2

And in second

3x+1=0

3x=-1

X=-1/3

Answered by kavitakokare
1

Step-by-step explanation:

(2x+3)(3x+1)=0

2x(3x+1)-3(3x+1)=0

6xsquare+9x+2x+3=0

3x(2x+3)+1(2x+3)

(2x+3=0)or(3x+1)

2x=-3 or 3x=-1

x=-3/2 or x=-1/2

hope it will help you

pls mark as brainlist

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