Question

Solve this Quadratic equation.
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Answer 1

Answer:

suppose x^1/5 is assume t

then quadratic equation will be

t^2 +5t + 6 = 0

then

we can write this

t^2+ 2t+5t+6=0

after rearrange this

t (t+2)+3 (t+2)=0

then

(t+2)(t+3)=0

t = -2

t=-3

but we know that x^1/5 = t

then x = (-2)^5

and x= (-3)^5

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