Question

Solve this quadratic equation

Answer 1

SOLUTION IS PROVIDED IN THE ATTACHMENT.

Hope it helps

Answer 2

Answer ⤵️

${x}^{2} - 4x + 5 = 0 \\ {x}^{2} - (5x - x) + 5 = 0 \\ {x}^{2} - 5x - x + 5 = 0 \\ x(x - 5) - 1(x - 5) = 0 \\ (x - 1)(x - 5) = 0 \\ x - 1 = 0 \\ x = 1 \\ x - 5 = 0 \\ x = 5$

So x can be 1 or 5

Step-by-step explanation:

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