solve this quadratic equation
Attachments:
Answers
Answered by
0
the answer would be 3/8
Answered by
0
let a and b represent alpha and beta
since a and b are the roots of the equation 3x^2 + 2x + 4
a + b = -b/a
=> a + b = -2/3 --- (1)
ab = c/a
=> ab = 4/3 --- (1)
now (1/a^2) + (1/b^2) = (b^2 + a^2)/(a^2 × b^2)
=> (a^2 + b^2)/(a^2 × b^2)
=> [(a + b)^2 - 2ab]/(ab)^2
=> [(-2/3)^2 - 2 × 4/3]/(4/3)^2
=> (4/9 - 8/3)/(16/9)
=> (4 - 3×8)/9/16/9
=> -20/16
=> -5/4
since a and b are the roots of the equation 3x^2 + 2x + 4
a + b = -b/a
=> a + b = -2/3 --- (1)
ab = c/a
=> ab = 4/3 --- (1)
now (1/a^2) + (1/b^2) = (b^2 + a^2)/(a^2 × b^2)
=> (a^2 + b^2)/(a^2 × b^2)
=> [(a + b)^2 - 2ab]/(ab)^2
=> [(-2/3)^2 - 2 × 4/3]/(4/3)^2
=> (4/9 - 8/3)/(16/9)
=> (4 - 3×8)/9/16/9
=> -20/16
=> -5/4
Similar questions