Math, asked by manebabaso58, 4 months ago

Solve this quadratic equation by factorisation method

1)3x2-2√6+2=0

2) 7m2=21m

3) m2-11=0​

Answers

Answered by Anonymous
1

Step-by-step explanation:

(1) x2 + 5x – 2 = 0

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(2) y2 = 5y – 10

Only one variable y.

Maximum index = 2

So, it is a quadratic equation.

(3) y2+

1

y

=2

⇒y3+1=2y

Only one variable y.

Maximum index = 3

So, it is not a quadratic equation.

(4) x+

1

x

=-2

⇒x2+1=-2x

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(5) (m + 2) (m – 5) = 0

⇒m2-3m-10=0

Only one variable m.

Maximum index = 2

So, it is a quadratic equation.

(6) m3 + 3m2 – 2 = 3m3

Only one variable m.

Maximum index = 3

So, it is not a quadratic equation.


Anonymous: Nice
Answered by singhyogendra559
1

Answer:

1) Given: 3x

2

−2

6

x+2=0

3x

2

6

x−

6

x+2=0,

3

x(

3

x−

2

)−

2

(

3

x−

2

)=0

(

3

x−

2

)(

3

x−

2

)=0∴

3

x−

2

=0 or

3

x−

2

=0

3

x=

2

or

3

x=

2

,x=

3

2

or x=

3

2

So, the root is repeated twice, one for each repeated factor (

3

x−

2

)l.

∴ The two equal roots of 3x

2

−2

6

x+2=0 are

3

2

,

3

2

2) 7

2

=

2

1

7

2

(

2

1

)

=

0

3) M

2

−11M+10

⇒M

2

−10M−M+10

⇒M(M−10)−1(M−10)

⇒(M−10)(M−1)

∴M

2

−11M+10=(M−1)(M−10).

please Mark my ans as Brainlist

.

Similar questions