solve this quadratic equation by factorization and check the solutions
9x^2 - 27x + 14 = 0
Answers
Answered by
2
Given Equation is 9x^2 - 27x + 14 = 0
= > 9x^2 - 21x - 6x + 14 = 0
= > 3x(3x - 7) - 2(3x - 7) = 0
= > (3x - 2)(3x - 7) = 0
(1)
3x - 2 = 0
= > 3x = 2
= > x = (2/3).
(2)
3x - 7 = 0
= > 3x = 7
= > x = (7/3).
Verification:
When x = (2/3):
= > 9(2/3)^2 - 27(2/3) + 14
= > 9(4/9) - 18 + 14
= > 4 - 4
= > 0.
when x = (7/3):
= > 9(7/3)^2 - 27(7/3) + 14
= > 49 - 63 + 14
= > 49 - 49
= > 0.
Hope this helps!
= > 9x^2 - 21x - 6x + 14 = 0
= > 3x(3x - 7) - 2(3x - 7) = 0
= > (3x - 2)(3x - 7) = 0
(1)
3x - 2 = 0
= > 3x = 2
= > x = (2/3).
(2)
3x - 7 = 0
= > 3x = 7
= > x = (7/3).
Verification:
When x = (2/3):
= > 9(2/3)^2 - 27(2/3) + 14
= > 9(4/9) - 18 + 14
= > 4 - 4
= > 0.
when x = (7/3):
= > 9(7/3)^2 - 27(7/3) + 14
= > 49 - 63 + 14
= > 49 - 49
= > 0.
Hope this helps!
siddhartharao77:
:-)
Answered by
1
9x^2 - 21x - 6x + 14 = 0
= 3x(3x - 7) - 2(3x - 7) = 0
= (3x - 2)(3x - 7) = 0
= x = 2/3 , 7/3
-b/a = 27/9 = 3 Also, 2/3 + 7/3 = 3
c/a = 14/9 Also, 2/3 x 7/3 = 14/9
= 3x(3x - 7) - 2(3x - 7) = 0
= (3x - 2)(3x - 7) = 0
= x = 2/3 , 7/3
-b/a = 27/9 = 3 Also, 2/3 + 7/3 = 3
c/a = 14/9 Also, 2/3 x 7/3 = 14/9
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