Question

SOLVE THIS QUADRATIC EQUATION BY FORMULA BSQUARE-4AC

2X^2-ROOT3X+1=0

Answer 1

Step-by-step explanation:

plz mark me brainlist thanx

Answer 2

solution of the quadratic equation is $x=\frac{-\sqrt{3}+\sqrt{-5}}{4}$   and $x=\frac{-\sqrt{3}-\sqrt{-5}}{4}$

             

Step-by-step explanation:

Given the quadratic equation

                $2x^{2} -\sqrt{3} x+1=0$

This quadratic equation is of the form $ax^{2} +bx+c=0$

  comparing both these equation we get ,

            $a=2, b = -\sqrt{3} , c =1$

   Discriminant D = $b^{2} -4ac$

                        or D = $(\sqrt{3} )^{2} -4\times 2\times1$

                         or D = $3-8$

                          or D= -5

Discriminant is negative.

So this quadratic equation has no real solution.

solution is $x=\frac{-b\pm\sqrt{b^{2} -4ac}}{2a}$

              or $x=\frac{-\sqrt{3}\pm\sqrt{-5}}{2\times2}$

              or $x=\frac{-\sqrt{3}+\sqrt{-5}}{4}$   and $x=\frac{-\sqrt{3}-\sqrt{-5}}{4}$