Question

solve this quadratic equation by quadratic formula please need solution urgently!​

Answer 1

Answer:

x = 1/4

Step-by-step explanation:

Multiply the equation by 8

16x^2 - 8x + 1 = 0

Breaking the middle term:

16x^2 - 4x - 4x + 1 = 0

4x(4x - 1) - 1(4x-1) = 0

(4x-1)^2 = 0

4x -1 = 0

x = 1/4

Answer 2

$2 {x}^{2} \times 8 - x \times 8 + \frac{1}{8} = 0$

$16 {x}^{2} - 8x + 1 = 0$

$a = 16 \: b = - 8 \: \: c = 1$

${b}^{2} - 4ac = { - 8}^{2} - 4 \times 16 \times 1$

${b}^{2} - 4ac = 64 - 64$

${b}^{2} - 4ac = 0$

$x = - b + - \frac{ \sqrt{ {b}^{2 - 4ac} } }{2a}$

$x = \frac{8 + - \sqrt{0} }{2 \times 16}$

$x = \frac{8}{32}$

$x = \frac{1}{4}$