Question

Solve this quadratic equation for using quadratic formula.

${p}^{2}{x}^{2} + ( {p}^{2} - {q}^{2} )x - {q}^{2} = 0$
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Answer 1

Step-by-step explanation:

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Answer 2

First , finding discriminant D=b²-4ac

D=(p²-q²)² -4×p²×-q²

= p⁴+q⁴-2p²q²+4p²q²

=p⁴+q⁴+2p²q²

=( p²+q²)²

So, √D=p²+q²

Now by quadratic formula,

x=. -b+_√D/2a

=. - (p²-q²) + p²-q²/2p²

=0/2p²

x=0

And,

x= -(p²-q²)-(p²-q²)/2p²

= -2(p²-q²)/2p²

= q²-p²/p²x

=(q²/p²)-1

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