Question

Solve this quadratic equation please :)

a/(ax-1) + b/(bx-1) = a+b ; where x is not equal to 1/a or 1/b

Please help guyz...(urgently needed)

Answer 1

a2bx2-(4ab+a2+b2)x-2 (a+b)=0
I have reduced this into quadratic equation where from u can solve

Answer 2

$= > \frac{a}{ax - 1} + \frac{b}{bx - 1} = a + b \\ \\ = > \frac{a}{ax - 1} - b = a - \frac{b}{bx - 1} \\ \\ = > \frac{a - abx + b}{ax - 1} = \frac{abx - a - b}{bx - 1} \\ \\ = > \frac{a - abx + b}{ - (a - abx + b)} = \frac{ax - 1}{bx - 1} \\ \\ = > - 1 = \frac{ax - 1}{bx - 1} \\ \\ = > - bx + 1 = ax - 1 \\ \\ = > - bx - ax = - 1 - 1 \\ \\ > - x(a + b) = - 2 \\ \\ = > x = \frac{2}{a + b}$
___________________[◢ANSWER]

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