Question

solve this quadratic equation plzz​

Answer 1

Answer:

-1&1/2

Step-by-step explanation:

Given below

Answer 2

x/x-1 + x-1/x = 4

=> x(x)/x(x-1) + (x-1)^2/x(x-1) = 4

=> x^2/(x^2-x) + (x^2+1-2x)/(x^2-x) = 4

=> (x^2 + x^2 - 2x + 1)/(x^2-x) = 4

=> 2x^2 + 2x + 1 = 4x^2 - 4x

=> 2x^2 - 4x^2 - 2x + 4x + 1 = 0

=> -2x^2 + 2x + 1 = 0

=> 2x^2 - 2x - 1 = 0

using quadratic formula,

=> x = (-b±√b²-4ac)/2a

=> x = (2±√12)/4

=> x = 2+√12/4 , x = 2-√12/4