Question

solve this quadratic equation:x²- 5x- 10=0 using the eqn.​

Answer 1

Answer:

first multiply x square into 10

then we get 10 x square

now split the 5 x in a way so that by multiplying you get 10 x square by adding and subtracting you get 5x

Answer 2

Equation: x² - 5x - 10 = 0

On comparing this equation with the standard form of quadratic equation ( i.e., ax² + bc + c = 0 ) , we get

a = 1 , b = -5 , c = -10

Now using the Quadratic equation, we get

$</p><p> \sf \rightarrow \quad x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \\ \\</p><p></p><p> \sf \rightarrow \quad x = \dfrac{ - ( -5) \pm \sqrt{ (-5)^{2} - 4 \times 1 \times -10} }{ 2 \times 1 }</p><p>\\ \\</p><p></p><p> \sf \rightarrow \quad x = \dfrac{ 5 \pm \sqrt{65} }{ 2 } \\ \\</p><p></p><p> \sf \rightarrow \quad x_{1} = \dfrac{ 5 + \sqrt{65} }{ 2 } \\ \\</p><p></p><p>\sf also,</p><p></p><p>\\ \\</p><p></p><p> \sf \rightarrow \quad x_{2} = \dfrac{5 - \sqrt{65}}{2}</p><p>$

Hence, The zeroes of the given quadratic equation are $\sf \dfrac{5 + \sqrt{65}}{2} \; and \; \dfrac{5 - \sqrt{65}}{2}$