Question

solve this quadratic equations...
find value of x​

Answer 1

(2x/x-4)+(2x-5)/(x-3) = 25/3

2x(x-3)+(2x-5)(x-4) = 25/3

(2x^-6x+2x^-5x-8x+20 )/(x^-3x-4x+12)= 25/3

(4x^-19x+20)/(x^-7x+12) = 25/3

3(4x^-19x+20) = 25(x^-7x+12)

12x^-57x+60 = 25x^-175x+300

7x^-118+240 = 0

x =-b+-√( b^ -4ac)/2a

x = 118+-√(13924-6720)/14

x = 118+-√7204/14

x = 59+-√1801/7

x = 59+√1801/7 or 59-√1801/7

Hope it helps...