Question

solve this qudratic equation 2x^2+5/3x-2=0​

Answer 1

$\underline{\underline{\maltese\: \: \textbf{\textsf{Answer}}}}$

${2x}^{2} + \frac{5}{3} x−2=0 \\ \\ \dashrightarrow {6x}^{2} +5x−6=0 \ \\ \\ \dashrightarrow {6x}^{2}−4x+9x−6=0 \\\\\dashrightarrow2x(3x−2)+3(3x−2)=0 \\ \\ \dashrightarrow(3x−2)(2x+3)=0 \\ \\\dashrightarrow (x−32)(x+23)=0 \\ \\\dashrightarrow x=32,−23$

Answer 2

$\underline{\underline{\maltese\: \: \textbf{\textsf{Answer}}}}$

${2x}^{2} + \frac{5}{3} x−2=0 \\ \\ \dashrightarrow {6x}^{2} +5x−6=0 \ \\ \\ \dashrightarrow {6x}^{2}−4x+9x−6=0 \\\\\dashrightarrow2x(3x−2)+3(3x−2)=0 \\ \\ \dashrightarrow(3x−2)(2x+3)=0 \\ \\\dashrightarrow (x−32)(x+23)=0 \\ \\\dashrightarrow x=32,−23$