Question

solve this que ...........​

Answer 1

Answer:

${\bf{\green{let, }}}$${\bf{\red{mass}}}$${\bf{\blue{of}}}$${\bf{\pink{the}}}$${\bf{\green{'H' }}}$${\bf{\orange{atom}}}$${\bf{\blue{mH=m}}}$

${\bf{\red{mass}}}$${\bf{\green{of}}}$${\bf{\pink{'Cl' }}}$${\bf{\blue{atom}}}$${\bf{\red{mCl=35.5m}}}$

${\bf{\red{let,}}}$${\bf{\blue{'H' }}}$${\bf{\pink{is}}}$${\bf{\green{in}}}$${\bf{\orange{origin}}}$${\bf{\blue{in}}}$${\bf{\red{the}}}$${\bf{\green{system}}}$${\bf{\pink{coordinates}}}$

${\bf{\orange{XH=0}}}$${\bf{\green{,XCl=1.27A°}}}$

${\bf{\blue{using}}}$${\bf{\pink{formula l}}}$${\bf{\green{for}}}$${\bf{\orange{the}}}$${\bf{\blue{center}}}$${\bf{\red{of}}}$${\bf{\green{the}}}$${\bf{\pink{mass}}}$${\bf{\blue{of}}}$ ${\bf{\green{the}}}$${\bf{\red{system }}}$${\bf{\blue{of}}}$${\bf{\pink{two}}}$${\bf{\green{particles}}}$

${\bf{\orange{=>Xcm=mHxH+mClxCl/mH+mCl}}}$

${\bf{\green{=>Xcm=35.5×xCl/35.5+1}}}$

${\bf{\red{=>35.5xCl/36.5}}}$

${\bf{\blue{=>35.5/36.5×(1.27)}}}$

${\bf{\pink{=>0.972×1.27}}}$

${\bf{\green{=>1.2344A°}}}$

${\bf{\orange{=>1.24A°(approx)}}}$

Answer 2

Answer:

let mass of the H atom mH=m

↣mass of Cl

′

↣ atom mCl=35.5m

let H is in origin in the system coordinates -

☉ XH=0

☉ XCl=1.27A°

Using formula for the center of mass of the system of twoparticles:

✒Xcm=mHxH+mClxCl/mH+mCl

✒Xcm=mHxH+mClxCl/mH+mCl

✒Xcm=35.5×xCl/35.5+1

✒Xcm=35.5×xCl/35.5+1

✒35.5xCl/36.5=>35.5xCl/36.5

✒35.5/36.5×(1.27)=>35.5/36.5×(1.27)

✒0.972×1.27=>0.972×1.27

✒1.2344A°=>1.2344A°

✒1.24A°(approx)

--- 1.24A°(approx)..✍

⛄ Thank You ⛄