Question

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Answer 1

Suppose the two players did not play at all so that the remaining (n-2) players played n−2C2

matches. Since these two players played 3 matches each, hence the total number of matches is n−2C2 + 3 + 3 = 84 (given) 

12(n−2)(n−3)=78

or n2−5n+6=156 or n2 - 5n - 150 = 0

or (n-15) (n+10) = 0 ∴ n = 15 (n =−10)

Answer is 15

Hope this helps you dear....

Answer 2

Answer:

28 participants....

Step-by-step explanation:

There should be 28 participants in the starting as each participant play 3 games so if you want to find the participants in starting you have to divide 84 by 3 As there is total 84 tournaments and each player plays 3 games= 84÷3=28

Hope this will help you...

Thank you for for points...