Question

solve this ques of jee mains
chapter → vectors​

Answer 1

Solution :-

Refer attachment...

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Answer 2

Answer:

F₁ = 4i+j-3k

F₂ = 3i+j-k

Total force, F⃗ = F₁ + F₂

= 7i+2j-4k

Particle displaces from a point i+2j+3k to the point 5i+4j+k.

Displacement,

⃗d = (5i+4j+k)-(i+2j+3k) {final - initial}

= 4i+2j-2k

∴work done , W = F⃗•d⃗

= (7i+2j-4k)•(4i+2j-2k)

= 28 + 4 + 8 = 40 units.