solve this ques of jee mains
chapter → vectors
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Answer: c) PA + PB – 2PC = 0
Solution: PA = PC + CA
PB = PC + CB
PA + PB =2 PC +( CA + CB ) =2 PC
(∵ CA =− CB )
Therefore,
PA + PB – 2PC = 0
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5
Option A is correct
PA=PC+CA
PB=PC+CB
PA+PB=2PC+(CA+CB)=2PC (Since,CA=-CB)
Therefore,PA+PB=2PC
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