solve this ques...plz don't ans senseless
Attachments:
Answers
Answered by
3
'......................
Attachments:
karn89:
any doubt then asked to me
tq
Answered by
2
Given x,y,z are in AP
So,
2y= x+z
y= (x+z)/2
Again',
x,y, (z+) are in GP.
So,
y² = x(z+1)
= x(z+1)
{ (x+z)/2}² = x(z+1).......from equation (I)
On solving we get ,
(x-z)² =4x
see picture
So,
2y= x+z
y= (x+z)/2
Again',
x,y, (z+) are in GP.
So,
y² = x(z+1)
= x(z+1)
{ (x+z)/2}² = x(z+1).......from equation (I)
On solving we get ,
(x-z)² =4x
see picture
Attachments:
Similar questions