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Answers
Answer:
a bird flies for 4 s with velocityof (t-3)
Step-by-step explanation:
Velocity, u=∣t−3∣
Time, t=4 s
at t=0, u=2 m/s
t=2, u=0 m/s
t=4 ,u=3 m/s
between time t=0 to t=2sec
a=
2
0−2
=−1 m/s
2
s
1
=ut+
2
1
at
2
s
1
=2×2+
2
1
×(−1)×4=2
Between time t=2 to t=4sec
a=
2
0−2
=1 m/s
2
s
2
=
2
1
×1×4=2
Thus,
Total distance;
s
1
+s
2
=2+2=4 m
Thus, during the 4 seconds, the bird travels a distance of 4 m.
At zero time bird was traveling at a speed of
0 - 3 = - 3 mets/sec in reverse direction say towards west. In one sec it travelled 3 met.
After one sec the speed of bird was :
1 - 3 = - 2 mets/sec. In west side , it travelled for one sec.
After 2 secs speed was : 2 - 3 = - 1 met / sec.
After 3 secs speed was 3 - 3 = 0 mets/sec ( it stops and reversed it direction say towards East.
And for next 3 seconds say 4th , 5th & 6th secs it travels same distance and reaches its starting point.
Towards west it travelled 3+ 2++1 = 6 mets.
And towards East it travelled : 1+2+3 = 6mets.
Total distance travelled = 6 + 6 = 12 mets.
While displacement is - 6 + 6 = 0 mets
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