Question

solve this question​

Answer 1

sp = bp also <B=60

SO SBP is equilateral

let side of triangle be a

BP = a/3

area of SBP = √3/4. ( a/3)^2

= √3 a^2/36

Area of RQC = √3 a^2/36 ( same)

area of SBP+ RQC = 2√3 a^2/36

=√3 a^2/18

area of ABC = √3 a^2/4

area of ASPQR = √3 a^2 ( 1/4 - 1/18)

= √3 a^2 ( 9 -2)/36

= 7√3 a^2/36

ratio = 7√3 (4)/36( √3)

= 28/36

= 7/9