Question

solve this question ​

Answer 1

6x^2- 7x- 3

= 6x^2+ 2x- 9x-3

= 2x(3x+1)- 3(3x+1)

= (2x-3)(3x+1)

∴ 2x-3=0 => 2x=3 =>x=$\frac{3}{2}$

∴ 3x+1=0 => 3x= -1 => x=$\frac{-1}{3}$

Therefore, zeroes of the polynomial: $\frac{3}{2}$ and $\frac{-1}{3}$

$\alpha+\beta$ = $\frac{-b}{a}$

=> $\frac{7}{6}$ = $\frac{7}{6}$          hence proven.

$\alpha\beta$ = $\frac{c}{a}$

=> $\frac{-3}{6}$ = $\frac{-3}{6}$          hence proven.

There you go...hope it helped. plz mark it as the brainliest!