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SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT
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Answered by
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Answer:
=> (secA+tanA)(1-sinA)
=> secA+tanA-secA×sinA-tanA×sinA
=> (1/cosA)+tanA-tanA-(sin²A/cosA)
=> (1/cosA)-(sin²A/cosA)
=> (1-sin²A)/cosA
=> cos²A/cosA
=> cosA
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