CBSE BOARD X, asked by kssne, 1 year ago

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Answered by Anonymous

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SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

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Answered by Anonymous

3

Answer:

=> (secA+tanA)(1-sinA)

=> secA+tanA-secA×sinA-tanA×sinA

=> (1/cosA)+tanA-tanA-(sin²A/cosA)

=> (1/cosA)-(sin²A/cosA)

=> (1-sin²A)/cosA

=> cos²A/cosA

=> cosA

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