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Hope this help you....
Step-by-step explanation:
A)
3x^3-x^2y+6x^2y-2xy^2+3xy^2-y^3
=x^2(3x-y)+2xy(3x-y)+y^2(3x-y)
=(3x-y)(x^2+2xy+y^2)
=(3x+y)(x+y)^2
=(3x+y)(x+y)(x+y)
B)(x+4)^3-9x-36
=(x+4)^3-9(x+4)
=(x+4)[(x+4)^2-9]
=(x+4)[(x+4)^2-3^2]
=(x+4)[(x+4+3)(x+4-3)]
=(x+4)(x+7)(x+1)
Answered by
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Step-by-step explanation:
3x^3-x^2y+6x^y-2xy^2+3xy^2-y^3
=3x^3-5x^2y-xy^2-y^3
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