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34 ) W = dV X Q
W = 12 X 2
= 24 joules
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35) a) Inversaly proportional to resistance
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36) R = pl/A
l/A = 4
cas2: 1/4 X4
= 1
resistence will be 1 Ω
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___________________________________
34 ) W = dV X Q
W = 12 X 2
= 24 joules
___________________________________
35) a) Inversaly proportional to resistance
___________________________________
36) R = pl/A
l/A = 4
cas2: 1/4 X4
= 1
resistence will be 1 Ω
____________________________________
Answered by
0
#34. Work done= Potential difference(V) × Charge(Q)
V=12v
Q=2C
Work done= 12×2 =24 Joule ⇒ option (2)
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#35.According to Ohms law
V=IR
I=V/R
So,current,I is inversely proportional to Resistance. ⇒ Answer is option (1)
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#36.Resistance=ρl/A
R= 4=ρl/A
Now given what if length=l/2 and Area=2A
R=ρl/2×2A =(1/4)×ρl/A
=(1/4)×4 [R=ρl/A = 4]
=1 ohm ⇒option (3)
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V=12v
Q=2C
Work done= 12×2 =24 Joule ⇒ option (2)
__________________________________________________________
#35.According to Ohms law
V=IR
I=V/R
So,current,I is inversely proportional to Resistance. ⇒ Answer is option (1)
____________________________________________________________
#36.Resistance=ρl/A
R= 4=ρl/A
Now given what if length=l/2 and Area=2A
R=ρl/2×2A =(1/4)×ρl/A
=(1/4)×4 [R=ρl/A = 4]
=1 ohm ⇒option (3)
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