Solve this question........
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Bubbly11:
please help me in maths
Nikita Singh
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sin20(4+sec29)
sec20
not 29
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8
6)
Let's solve step by step
•4/(216)^-2/3
⇒4/(6³)^-2/3
⇒4/6^-2
⇒ 4×6²
⇒4×36 = 144
•1/256^-3/4
⇒1/(4⁴)^-3/4
⇒1/4^-3
⇒1×4³ = 1×64 = 64
•2/243^-1/5
⇒2/(3^5)^-1/5
⇒2/3^-1
⇒2×3¹ = 2×3 = 6
Here we used the principle 1/a^-n = a^n
As per question, we need to find
4/216^-2/3 + 1/256^-¾ + 2/243^-1/5
⇒144+64+6
⇒214
Hope it helps
Let's solve step by step
•4/(216)^-2/3
⇒4/(6³)^-2/3
⇒4/6^-2
⇒ 4×6²
⇒4×36 = 144
•1/256^-3/4
⇒1/(4⁴)^-3/4
⇒1/4^-3
⇒1×4³ = 1×64 = 64
•2/243^-1/5
⇒2/(3^5)^-1/5
⇒2/3^-1
⇒2×3¹ = 2×3 = 6
Here we used the principle 1/a^-n = a^n
As per question, we need to find
4/216^-2/3 + 1/256^-¾ + 2/243^-1/5
⇒144+64+6
⇒214
Hope it helps
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