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let y^2 =x
therefore x^2 +4x -32 =0
x^2 +8x -4x -32 =0
x(x+8) -4(x+8)=0
(x-4)(x+8)=0
putting value x=y^2
(y^2-4)(y^2+8)=0
(y-2)(y+2)(y^2+8)
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