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Answered by
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Hi very nice question
see given,
p(x)= x^3-ax^2+6x-a
g(x)= x-a
r(x)= ?
now
kindly see my image
we get
r(x) = 5a
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
see given,
p(x)= x^3-ax^2+6x-a
g(x)= x-a
r(x)= ?
now
kindly see my image
we get
r(x) = 5a
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Attachments:
rishilaugh:
nice answer abinash
nice ans buddy
Answered by
2
Hey friend!
Given:p(x)=x^3-ax^2+6-a
g(x)=x-a
p(x)/g(x)=q(x)+r(x)
=(x^2+6)+5a
Here ,remider =r(x)=5a
___________________
___________________
HOPE IT HELPZ
Given:p(x)=x^3-ax^2+6-a
g(x)=x-a
p(x)/g(x)=q(x)+r(x)
=(x^2+6)+5a
Here ,remider =r(x)=5a
___________________
___________________
HOPE IT HELPZ
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ty :)
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