Question

Solve this question.

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Answer 1

Answer:

1. qb=rc

in tri. qcr and tri. qbp

CQ=pb (given)

angle c= angle b(90°)

angle rqc =angle qbp(v.o.a)

tir. qcr=tir.qbp by ASA

so,

qb =ra by c.p .c.t.

2. pq=qr by c.p.c.t.

3. in tri. rpq

p+r+q=180

(let p and r is x )

x+x+90=180

2x =180-90

2x =90

x= 90÷2

x=45°

p=x=45°

r=x=45°