Math, asked by surajgorai5560, 1 year ago

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Answered by mysticd
1

Answer:

f\left(f\big(\frac{1}{x}\big)\right)=\frac{1}{x-1}

Step-by-step explanation:

f(x)=1-\frac{1}{x}\:---(1)

f\left(\frac{1}{x}\right)=1-\frac{1}{\frac{1}{x}}\\=1-x \:---(2)

Now,\\f\left(f\big(\frac{1}{x}\big)\right)\\=1-\frac{1}{1-x}\\=\frac{1-x-1}{1-x}\\=\frac{-x}{1-x}\\=\frac{1}{x-1}

Therefore,

f\left(f\big(\frac{1}{x}\big)\right)=\frac{1}{x-1}

•••♪

Answered by nalinsingh
1

Answer:

Step-by-step explanation:

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