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(tan 20° x cot 70°) - (sec 20° x cosec 70°)
= (tan(90°-70° x cot70°) - (sec(90°-70° x cosec 70°)
= (cot 70° x cot 70°) - (cosec 70° x cosec 70°)
(As tan - cot and sec - cosec are complementary)
= cot^2 20° - cosec^2 20°
= 1
Since cot^2 α - cosec^2 α = 1
Therefore, the answer is
Hope this helps you.
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