Question

Solve this question ​

Answer 1

Answer:

In ∆PQS and ∆RQS,

QP=QR( equidistant chords are equal in

length)

angle QPS=angle QRS(angle in a semi circle is

always 90°)

QS=QS(common)

Therefore,∆PQS and ∆RQS are congruent

(by R-H-S congruency

angle PQS=angle RQS(by c.p.c.t)

Therefore,angle PQR is bisected.[proved]

angle PSQ=angle RSQ(by c.p.c.t)

Therefore,angle PSR is bisected.[proved]

Step-by-step explanation:

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