Question

solve this question​

Answer 1

$= > {(x + 3)}^{2} + {(y - 5)}^{2} = {(x - 5)}^{2} + {(y - 1)}^{2} \\ = > {x}^{2} + 6x + 9 + {y}^{2} - 10y + 25 = {x}^{2} - 10x + 25 + {y}^{2} - 2y + 1 \\ = > 6x - 10y + 34 = - 10x - 2y + 26 \\ = > 16x - 8y = - 8 \\ = > 8(2x - y) = - 8 \\ = > 2x - y = - 1 \\ = > 2x - y + 1 = 0$

so the eqn is

$2x - y + 1 = 0$