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DATA- ABCD is a parallelogram
AC and BD are diagonals intersecting at M
TO PROVE- M is mid point of LN
PROOF- In ΔAML and ΔCMN
∠MAL = ∠MCN(alternate interior angles)
∠AML = ∠CMN(vertically opposite angles)
AM = CM (diagonals in a parallelogram bisect each other)
∴ ΔAML ≈ ΔCMN
∴LM = NM (cpct)
∴M is the midpoint of LN
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angel DMC=90°
angel dma=90°
angel amb=90°
angel bmc=90° its proved adcb=360° so proved that m is a midd point becaused same angel distribution .
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