Question

solve this question
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Answer 1

Answer:

DATA- ABCD is a parallelogram

            AC and BD are diagonals intersecting at M

TO PROVE-  M is mid point of LN

PROOF- In  ΔAML and ΔCMN

               ∠MAL = ∠MCN(alternate interior angles)

               ∠AML = ∠CMN(vertically opposite angles)

               AM = CM (diagonals in a parallelogram bisect each other)

           ∴ ΔAML ≈ ΔCMN

        ∴LM = NM (cpct)

    ∴M is the  midpoint of LN

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Answer 2

angel DMC=90°

angel dma=90°

angel amb=90°

angel bmc=90° its proved adcb=360° so proved that m is a midd point becaused same angel distribution .