Math, asked by palirana95, 11 months ago

solve this question​

Attachments:

Answers

Answered by abhi569
5

Answer:

Required value of x / y is 4 / 17 or 1 / 2.

Step-by-step explanation:

Given,

34x^2 - 25xy + 4y^2 = 0

On dividing both sides by y^2 :

= > ( 34x^2 - 25xy + 4y^2 ) / y^2 = 0 / y^2

= > 34( x^2 / y^2 ) - 25( xy / y^2 ) + 4( y^2 / y^2 ) = 0 { y 0 }

= > 34( x / y )^2 - 25( x / y ) + 4( 1 ) = 0

= > 34( x / y )^2 - 25( x / y ) + 4 = 0

Let x / y = a, so x^2 / y^2 = a^2

= > 34a^2 - 25a + 4 = 0

= > 34a^2 - ( 8 + 17 )a + 4 = 0

= > 34a^2 - 8a - 17a + 4 = 0

= > 2a( 17a - 4 ) - ( 17a - 4 ) = 0

= > ( 17a - 4 )( 2a - 1 ) = 0

Using zero product rule,

17a - 4 = 0 or 2a - 1 = 0

a = 4 / 17 or a = 1 / 2

x / y = 4 / 17 or x / y = 1 / 2

Hence the required value of x / y is 4 / 17 or 1 / 2.

Similar questions