Question

solve this question ​

Answer 1

Answer:

here is your answer I think from here on you can solve now ....

Answer 2

$\large{ \bold{ \red{ \underline{ \underline{Question...}}}}}$

$\large{ \sf{rationalize \: \frac{ \sqrt{3 } + 1 }{2 \sqrt{2} - \sqrt{3} }}}$

$\large{ \green{ \bold{ \underline{ \underline{Answer...}}}}}$

$\large{ \sf{ = \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{5} }}$

$\large{ \bold{ \red{ \underline{ \underline{Solution...}}}}}$

$\large{ \sf{ \to \: \frac{ \sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3} } }} \\ \\ \large{ \sf{ \to \: \frac{ (\sqrt{3} + 1)(2 \sqrt{2} + \sqrt{3}) }{(2 \sqrt{2} - \sqrt{3} )(2 \sqrt{2} + \sqrt{3}) } }} \\ \\ \large{ \sf{ \to \: \frac{2 \sqrt{6} + 3 + 2 \sqrt{2 } + \sqrt{3} }{(2 \sqrt{2}) {}^{2} - ( \sqrt{3}) {}^{2} } }} \\ \red{ \large{ \sf{by \: using \: (x - y)(x + y) = {x}^{2} - {y}^{2} in denominator}}} \\ \\ \large{ \sf{ \to \: \frac{ 2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{8 - 3} }} \\ \\ \large{ \sf{ \boxed{ \green{ \to \: \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{5} }}}}$

$\large{ \bold{ \pink{ required \: answer \: is = \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{5} }}}$