Question

Solve this question ​

Answer 1

Answer:

Explanation:

1) 65 maths

Step-by-step explanation:

Let the set of students who offered mathematics, statistics and physics  be M, S and P respectively. Let a be number of students who offered all 3 subjects.  So we get

40 – a  +  a + 20 – a  + 8 = 65

So 68 – a = 65

 A = 3

Now students who offered Mathematics  

 15 + 10 – a + a + 40 – a

 65 – a

65 – 3 = 62

Now students who offered physics

12 + 10 – a + a + 20 – a

42 – a  

42 – 3 = 39

Now students who offered any of three subjects are

15 – 12 + 8 + 10 – a + 40 – a + 20 – a + a

105 – 2 a  

105 – 2 x 3

105 – 6

= 99

So number of students who did not offer any subjects were 100 – 99 = 1        

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